College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.6 - Page 86: 39

Answer

$\frac{3}{x-3}$

Work Step by Step

Since both expressions have common denominators, you can simply combine their numerators. $\frac{x^2+3x}{x^2+x-12}-\frac{x^2-12}{x^2+x-12}$ $\frac{3x+12}{x^2+x-12}$ $\frac{3(x+4)}{(x+4)(x-3)}$ $\frac{3}{x-3}$
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