Answer
$\frac{x-2}{x-3}; x \ne 3,-2$
Work Step by Step
$ =\frac{x^{2}-4x}{x^{2}-x-6} + \frac{4x-4}{x^{2}-x-6}$
Same denominator - add numerators.
$ =\frac{x^{2}-4x+4x-4}{x^{2}-x-6}$
Combine like terms.
$ =\frac{x^{2}-4}{x^{2}-x-6}$
Factor
$ =\frac{(x+2)(x-2)}{(x+2)(x-3)}; x \ne 3,-2;$
$=\frac{x-2}{x-3}; x \ne 3,-2$
