Answer
$$\lim _{h \rightarrow 0} \frac{\sin (\sin h)}{\sin h} =1$$
Work Step by Step
Given $$\lim _{h \rightarrow 0} \frac{\sin (\sin h)}{\sin h} $$
Let $ x=\sin h \ \Rightarrow $ at $ h=0 $, we get $ x\rightarrow \sin 0=0$
So, we get
\begin{aligned} L&=\lim _{h \rightarrow 0} \frac{\sin (\sin h)}{\sin h} \\
&= \lim _{x \rightarrow 0} \frac{\sin x}{x} \\
&=1
\end{aligned}