Answer
$\frac{4(x^{2}-1)}{12(x+2)(x-1)}=\frac{(x+1)}{3(x+2)}$
Work Step by Step
$\frac{4(x^{2}-1)}{12(x+2)(x-1)}=\frac{4(x-1)(x+1)}{12(x+2)(x-1)}=\frac{(x+1)}{3(x+2)}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises - Page 43: 16
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