Answer
$\frac{x^{2}-x-2}{x^{2}-1}=\frac{x-2}{x-1}$
Work Step by Step
$\frac{x^{2}-x-2}{x^{2}-1}=\frac{(x-2)(x+1)}{(x+1)(x-1)}=\frac{x-2}{x-1}$
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