Answer
$\frac{y-6}{2y+1}$
Work Step by Step
factor both the numerator and denominator:
from : $\frac{y^{2}-3y-18}{2y^{2}+7y+3}$
to: $\frac{(y-6)(y+3)}{(2y+1)(y+3)}$
then cancel like terms: (y+3):
$\frac{(y-6)}{(2y+1)}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises - Page 43: 22
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