Answer
$\frac{2x^{2}+3x}{2x-3}$
Work Step by Step
$\frac{2x^{3}-x^{2}-6x}{2x^{2}-7x+6}$ = $\frac{x(2x^{2}-x-6)}{2x^{2}-7x+6}$ = $\frac{x(2x+3)(x-2)}{(2x-3)(x-2)}$ = $\frac{x(2x+3)}{(2x-3)}$ = $\frac{2x^{2}+3x}{2x-3}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises - Page 43: 23
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