Answer
$\frac{1}{4(x-2)}$
Work Step by Step
$=\frac{4x}{x^2-4}\times\frac{x+2}{16x}$
Multiply the two:
$=\frac{4x(x+2)}{16x(x^2-4)}$
Cancel out the x-variable:
$=\frac{4(x+2)}{16(x^2-4)}$
Factorise the $x^2-4$:
$=\frac{4(x+2)}{16(x+2)(x-2)}$
Cancel out the $x+2$:
$=\frac{4}{16(x-2)}$
Simplify the fraction:
$=\frac{1}{4(x-2)}$
