Answer
(i) $1.07 \space bar$
(ii) $803 \space torr.$
Work Step by Step
Boyle's law: $p_iV_i = p_fV_f$
$$V_i - 1.80 \space dm^3 = V_f = 2.14 \space dm^3$$ $$V_i = 2.14 \space dm^3 + 1.80 \space dm^3 = 3.94 \space dm^3$$
$$p_i(3.94 \space dm^3) = (1.97 \space bar)(2.14 \space dm^3)$$ $$p_i = \frac{ (1.97 \space bar)(2.14 \space dm^3)}{3.94 \space dm^3} =
1.07 \space bar$$
$$1 \space atm = 1.01325 \space bar$$ $$760 \space torr. = 1 \space atm$$
$$1.07 \space bar \times \frac{1 \space atm}{1.01325 \space bar} \times \frac{760 \space torr.}{1 \space atm} = 803 \space torr$$
