Physical Chemistry: Thermodynamics, Structure, and Change

Published by W. H. Freeman
ISBN 10: 1429290196
ISBN 13: 978-1-42929-019-7

Chapter 1 - Topic 1A - The perfect gas - Exercises - Page 54: 1A.8(b)

Answer

$$P_4$$

Work Step by Step

1. Convert the values to K and Pa: $$T/K = 100 + 273.15 = 373.15$$ $$T = 373.15 \space K$$ $$p = 16.0 \space kPa= 16.0 \times 10^3 \space Pa = 16000 \space Pa$$ 2. Calculate the molar volume. $$pV_m = RT$$ $$V_m = \frac{RT}{p} = \frac{(8.31447 \space Pa \space m^3 \space K^{-1} \space mol^{-1})(373.15 \space K)}{16000 \space Pa}$$ $$V_m = 0.1939 \space m^3 \space mol^{-1}$$ 3. Find the molar mass: $$0.1939 \space m^3 \space mol^{-1} \times 0.6388 \space kg \space m^{-3} = 0.124 \space kg \space mol^{-1}$$ $$0.124 \times 10^3 \space g \space mol^{-1} = 124 \space g/mol$$ 4. Calculate the number of Sulfur atoms: $$1 \space Phosphorus \space atom = 31 \space g/mol$$ $$124 \space g/mol \times \frac{1 \space Phosphorus \space atom}{31 \space g/mol} = 4 \space Phosphorus \space atoms$$
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