Answer
$$p_2 = 27.6 \space lb \space in^{-2}$$
In order to calculate this value, we had to presume that the gas inside the car tire is a perfect gas. In practice, since the gas is not perfect, there may be some difference between the theoretical pressure and the experimental one.
Work Step by Step
1. Convert the temperature values to Kelvin scale:
$$T(K) = T(C^o) + 273.15$$ $$T_1(K) = (-5) + 273.15 = 268.15$$ $$T_2(K) = (35) + 273.15 = 308.15$$
2. Use the Combined gas law to calculate the final pressure:
$$\frac{p_1V_1}{n_1T_1} = \frac{p_2V_2}{n_2T_2}$$
Since $n$ and $V$ are constant:
$$\frac{p_1}{T_1} = \frac{p_2}{T_2}$$
Solving for the final pressure $p_2$:
$$\frac{p_1}{T_1} \times T_2 = p_2$$ $$\frac{p_1}{T_1} \times T_2 = p_2$$ $$p_2 = \frac{24 \space lb \space in^{-2}}{268.15 \space K} \times 308.15 \space K = 27.6 \space lb \space in^{-2}$$
