Physical Chemistry: Thermodynamics, Structure, and Change

Published by W. H. Freeman
ISBN 10: 1429290196
ISBN 13: 978-1-42929-019-7

Chapter 1 - Topic 1A - The perfect gas - Exercises - Page 54: 1A.8(a)

Answer

$$S_8$$

Work Step by Step

1. Convert the values to K and Pa: $$T/K = 500 + 273.15 = 773.15$$ $$T = 773.15 \space K$$ $$p = 93.2 \space kPa= 93.2 \times 10^3 \space Pa = 93200 \space Pa$$ 2. Calculate the molar volume. $$pV_m = RT$$ $$V_m = \frac{RT}{p} = \frac{(8.31447 \space Pa \space m^3 \space K^{-1} \space mol^{-1})(773.15 \space K)}{93200 \space Pa}$$ $$V_m = 0.06897 \space m^3 \space mol^{-1}$$ 3. Find the molar mass: $$0.06897 \space m^3 \space mol^{-1} \times 3.710 \space kg \space m^{-3} = 0.256 \space kg \space mol^{-1}$$ $$0.256 \times 10^3 \space g \space mol^{-1} = 256 \space g/mol$$ 4. Calculate the number of Sulfur atoms: $$1 \space Sulfur \space atom = 32 \space g/mol$$ $$256 \space g/mol \times \frac{1 \space Sulfur \space atom}{32 \space g/mol} = 8 \space Sulfur \space atoms$$
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