Physical Chemistry: Thermodynamics, Structure, and Change

Published by W. H. Freeman
ISBN 10: 1429290196
ISBN 13: 978-1-42929-019-7

Chapter 1 - Topic 1A - The perfect gas - Exercises - Page 54: 1A.5(b)

Answer

$$1.5 \times 10^3 \space Pa$$

Work Step by Step

Hydrostatic pressure = $\rho gh$ $\rho = 1.0 \space g/cm^3 \longrightarrow 1.0 \frac{g}{cm^3} \times \frac{10^6 \space cm^3}{1 \space m^3} \times \frac{1 \space kg}{1000 \space g} = 10^3 \space \frac{kg}{m^3}$ $g = 9.81 \space m/s^2$ $h = 15 \space cm \longrightarrow 15 \space cm \times \frac{1 \space m}{100 \space cm} = 0.15 \space m$ $$\rho gh = (10^3 \space kg/m^3)(9.81 \space m/s^2)(0.15 \space m) $$ $$ \rho gh= 1.5 \times 10^3 \space \frac{kg}{ms^2} = 1.5 \times 10^3 \space Pa$$
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