Answer
$\frac{2x+1}{2(x-3)}$
Work Step by Step
We simplify:
$\displaystyle \frac{5(x-3)(2x+1)}{10(x-3)^{2}}=\frac{5(x-3).(2x+1)}{5(x-3)2(x-3)}=\frac{2x+1}{2(x-3)}$
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