Answer
$\frac{1}{t^{2}+9}$
Work Step by Step
We factor the denominators and reduce:
$\displaystyle \frac{t-3}{t^{2}+9}*\displaystyle \frac{t+3}{t^{2}-9}=\frac{(t-3)(t+3)}{(t^{2}+9)(t-3)(t+3)}=\frac{1}{t^{2}+9}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises - Page 51: 29
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