Answer
$\frac{2x}{(x+1)(x-1)}$
Work Step by Step
We form a common denominator:
$\displaystyle \frac{1}{x+1}+\frac{1}{x-1}=\frac{x-1}{(x+1)(x-1)}+\frac{x+1}{(x+1)(x-1)}=\frac{x-1+x+1}{(x+1)(x-1)}=\frac{2x}{(x+1)(x-1)}$
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