Answer
$\frac{c}{c-2}$
Work Step by Step
We multiply by $c-1$ and simplify:
$\displaystyle \frac{1+\frac{1}{c-1}}{1-\frac{1}{c-1}}=\frac{(c-1)(1+\frac{1}{c-1})}{(c-1)(1-\frac{1}{c-1})}=\frac{c-1+1}{c-1-1}=\frac{c}{c-2}$
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