College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises - Page 51: 43

Answer

$\frac{2x+5}{(x+1)(x+2)}$

Work Step by Step

We form a common denominator: $\displaystyle \frac{3}{x+1}-\frac{1}{x+2}=\frac{3(x+2)}{(x+1)(x+2)}-\frac{x+1}{(x+1)(x+2)}=\frac{3x+6-x-1}{(x+1)(x+2)}=\frac{2x+5}{(x+1)(x+2)}$
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