Answer
$\frac{2x+5}{(x+1)(x+2)}$
Work Step by Step
We form a common denominator:
$\displaystyle \frac{3}{x+1}-\frac{1}{x+2}=\frac{3(x+2)}{(x+1)(x+2)}-\frac{x+1}{(x+1)(x+2)}=\frac{3x+6-x-1}{(x+1)(x+2)}=\frac{2x+5}{(x+1)(x+2)}$
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