Answer
$\frac{x+4}{x+1}$
Work Step by Step
We factor all terms and reduce:
$\displaystyle \frac{x^{2}+7x+12}{x^{2}+3x+2}*\frac{x^{2}+5x+6}{x^{2}+6x+9}=\frac{(x+3)(x+4)}{(x+1)(x+2)}*\frac{(x+2)(x+3)}{(x+3)(x+3)}=\frac{x+4}{x+1}$
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