Answer
$-\frac{1}{(1+x)(1+x+h)}$
Work Step by Step
We multiply by $(1+x)(1+x+h)$ to simplify the fractions:
$\displaystyle \frac{\frac{1}{1+x+h}-\frac{1}{1+x}}{h}=\frac{(1+x)-(1+x+h)}{h(1+x)(1+x+h)}=-\frac{1}{(1+x)(1+x+h)}$
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