Answer
$\frac{x(2x+3)}{2x-3}$
Work Step by Step
We simplify:
$\displaystyle \frac{2x^{3}-x^{2}-6x}{2x^{2}-7x+6}=\frac{x(2x^{2}-x-6)}{(2x-3)(x-2)}=\frac{x(2x+3)(x-2)}{(2x-3)(x-2)}=\frac{x(2x+3)}{2x-3}$
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