College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises - Page 51: 27

Answer

$\frac{x-3}{x+2}$

Work Step by Step

We factor the left side and reduce: $\displaystyle \frac{x^{2}+2x-15}{x^{2}-25}*\frac{x-5}{x+2}=\frac{(x+5)(x-3)(x-5)}{(x+5)(x-5)(x+2)}=\frac{x-3}{x+2}$
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