Answer
$\frac{3x+7}{(x+5)(x-3)}$
Work Step by Step
We form a common denominator:
$\displaystyle \frac{1}{x+5}+\frac{2}{x-3}=\frac{x-3}{(x+5)(x-3)}+\frac{2(x+5)}{(x+5)(x-3)}=\frac{x-3+2x+10}{(x+5)(x-3)}=\frac{3x+7}{(x+5)(x-3)}$
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