Answer
$\frac{2x+1}{x^{2}(x+1)}$
Work Step by Step
We form a common denominator:
$\displaystyle \frac{1}{x^{2}}+\frac{1}{x^{2}+x}=\frac{1}{x^{2}}+\frac{1}{x(x+1)}=\frac{x+1}{x^{2}(x+1)}+\frac{x}{x^{2}(x+1)}=\frac{2x+1}{x^{2}(x+1)}$
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