Answer
$\frac{y-6}{2y+1}$
Work Step by Step
We simplify:
$\displaystyle \frac{y^{2}-3y-18}{2y^{2}+7y+3}=\frac{(y-6)(y+3)}{(2y+1)(y+3)}=\frac{y-6}{2y+1}$
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