Answer
$\frac{3x+2}{(x+1)^{2}}$
Work Step by Step
We form a common denominator:
$\displaystyle \frac{x}{(x+1)^{2}}+\frac{2}{x+1}=\frac{x}{(x+1)^{2}}+\frac{2(x+1)}{(x+1)(x+1)}=\frac{x+2x+2}{(x+1)^{2}}=\frac{3x+2}{(x+1)^{2}}$
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