Answer
$$\frac{3}{2}$$
Work Step by Step
Given $$\lim _{x \rightarrow+\infty}\frac{3x+1}{2x-5}$$
Then
\begin{align*}
\lim _{x \rightarrow+\infty}\frac{3x+1}{2x-5}&=\lim _{x \rightarrow+\infty}\frac{\frac{3x}{x}+\frac{1}{x}}{\frac{2x}{x}-\frac{5}{x}}\\
&=\lim _{x \rightarrow+\infty}\frac{3+\frac{1}{x}}{2-\frac{5}{x}}\\
&=\frac{3}{2}
\end{align*}