Answer
$$0$$
Work Step by Step
Given $$\lim _{x \rightarrow \infty}\frac{1}{x-12}$$
Then
\begin{align*}
\lim _{x \rightarrow \infty}\frac{1}{x-12}&=\lim _{x \rightarrow \infty}\frac{1/x}{x/x-12/x}\\
&=\lim _{x \rightarrow \infty}\frac{1/x}{1-12/x}\\
&=\frac{0}{1-0}\\
&=0
\end{align*}