College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.6 - Page 87: 59

Answer

$\frac{1}{3}; x \ne 3;$

Work Step by Step

$\frac{\frac{x}{3}-1}{x-3} $ Taking LCD in numerator, $\frac{\frac{x}{3}-1}{x-3} = \frac{\frac{x-3}{3}}{x-3} ; x \ne 3; $ $= \frac{x-3}{3} \times \frac{1}{x-3} ; x \ne 3; $ $=\frac{1}{3}; x \ne 3;$
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