College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.6 - Page 87: 77

Answer

$\frac{1}{y(y+5)}; y \ne 0,-5;$

Work Step by Step

$\frac{y^{-1}- (y+5)^{-1}}{5}$ The given expression can be written as $=\frac{\frac{1}{y}- \frac{1}{y+5}}{5}; y \ne 0,-5;$ Take LCD in the numerator $=\frac{\frac{y+5-y}{y(y+5)}}{5}; y \ne 0,-5;$ $=\frac{\frac{5}{y(y+5)}}{5}; y \ne 0,-5;$ $ =\frac{5}{y(y+5)} \times \frac{1}{5}; y \ne 0,-5;$ $= \frac{1}{y(y+5)}; y \ne 0,-5;$
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