Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises - Page 34: 123

Answer

$3(x-1)(x+2)$

Work Step by Step

$Factor$ $the$ $expression$ $completely:$ $(x-1)(x+2)^2$ - $(x-1)^2(x+2)$ Factor out $(x-1)(x+2)$ from both terms $(x-1)(x+2)((x+2)-(x-1))$ Distribute the minus sign (-1) for $(x-1)$ in $((x+2)-(x-1))$ and simplify =$(x-1)(x+2)((x+2)+(-x+1))$ =$(x-1)(x+2)(x+2-x+1)$ =$ (x-1)(x+2)(3)$ =$3(x-1)(x+2)$
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