Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises - Page 34: 32

Answer

$49y^2 - 28y + 4$

Work Step by Step

Use the Square of a Difference Product Formula: $(A-B)^2 = A^2-2AB+B^2$ with $A=2$ and $B=7y$: $(2-7y)^2 = 2^2 - 2(2)(7y) + (7y)^2$ $=4 - 28y + 49y^2$ $=49y^2 - 28y + 4$
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