Answer
$3x^{3}-x^{2}+6x-2=(x^{2}+2)(3x-1)$
Work Step by Step
$3x^{3}-x^{2}+6x-2$
Group the first and second terms together. Do the same with the third and fourth terms:
$3x^{3}-x^{2}+6x-2=(3x^{3}-x^{2})+(6x-2)$
Take out common factor $x^{2}$ from the first parentheses and common factor $2$ from the second parentheses:
$...=x^{2}(3x-1)+2(3x-1)=...$
Finally, take out common factor $(3x-1)$:
$...=(x^{2}+2)(3x-1)$
