Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises - Page 34: 60

Answer

$(x+(2+x^{2}))(x-(2+x^{2}))=-x^{4}-3x^{2}-4$

Work Step by Step

$(x+(2+x^{2}))(x-(2+x^{2}))$ Rewrite by removing the inner parentheses: $(x+(2+x^{2}))(x-(2+x^{2}))=(x^{2}+x+2)(-x^{2}+x-2)=...$ Multiply each term of the first factor with every term of the second factor: $...=-x^{4}+x^{3}-2x^{2}-x^{3}+x^{2}-2x-2x^{2}+2x-4=...$ Combine like terms and simplify: $...=-x^{4}+(x^{3}-x^{3})+(-2x^{2}+x^{2}-2x^{2})+(-2x+2x)-4=$ $...=-x^{4}-3x^{2}-4$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.