Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises - Page 34: 68

Answer

$7xy^2(-x^3+2y+3y^2$)

Work Step by Step

$Factor$ $out$ $the$ $common$ $factor:$ $-7x^4y^2+14xy^3+21xy^4$ All the terms have a common factor of $7xy^2$ $\frac{-7x^4y^2}{7xy^2} = -x^3$ $\frac{14xy^3}{7xy^2} = 2y$ $\frac{21xy^4}{7xy^2} = 3y^2$ $=7xy^2(-x^3+2y+3y^2$)
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