Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises - Page 34: 58

Answer

$h^{2}$

Work Step by Step

Change square roots to exponents: $((h^{2}+1)^{1/2}+1)((h^{2}+1)^{1/2}-1)$ Multiply: $(h^{2}+1)^{2/2}-1$ Simplify: $h^{2}+1-1$ $h^{2}$
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