Answer
$(x^{2}+1)^{1/2}+2(x^{2}+1)^{-1/2}=\dfrac{x^{2}+3}{\sqrt{x^{2}+1}}$
Work Step by Step
$(x^{2}+1)^{1/2}+2(x^{2}+1)^{-1/2}$
Take out common afctor $(x^{2}+1)^{-1/2}$:
$(x^{2}+1)^{1/2}+2(x^{2}+1)^{-1/2}=(x^{2}+1)^{-1/2}[(x^{2}+1)+2]=...$
$...=(x^{2}+1)^{-1/2}(x^{2}+3)=\dfrac{x^{2}+3}{\sqrt{x^{2}+1}}$